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21 blue and 23 red balls Question

Initial State: You have a bag containing 21 blue balls and 23 red balls. There are an additional 22 red balls kept outside the bag.


The Rules: You must randomly pick two balls from the bag.

If the balls are of different colors (one red, one blue), you must put the blue ball back into the bag.

If the balls are of the same color, you remove them both and put a red ball back into the bag.


Objective: You repeat this process until only one ball remains in the bag.

Question:
Determine the color of that final ball?


Answer:

Since, we put back the blue colour, when odd number of colours ball we get, it mean, we will be ending up with odd number of blue colour, hence the last colour will be "Blue".